Answer
$y=-\displaystyle \frac{1}{4}x+2$
Work Step by Step
$y-y_{1}=m(x-x_{1})$
is the point-slope form: slope $m$ and line passes through $(x_{1}, y_{1})$.
Solve for y to obtain the form y=mx+b (slope-intercept)
$y-0=-\displaystyle \frac{1}{4}(x-8)$
$y=-\displaystyle \frac{1}{4}x+2$
