Answer
$ z = -ln(e^t + C)$
Work Step by Step
$ dz/dt + e^{t+z} = 0$
This can be rewritten as:
$ dz/dt = -e^{t+z}$
$ dz/dt = -e^te^z $
Now let's separate z and t:
$ e^{-z} dz = -e^t dt $
Now let's integrate both sides:
$\int e^{-z} dz = \int -e^t dt $
$-e^{-z} = -e^t + C $
To isolate z, we can add ln() on both sides:
$ ln(-e^{-z}) = ln(-e^t + C)$
$-z = ln(-e^t + C)$
$ z = -ln(-e^t + C)$