Answer
$\int$(e$^2$$^x$ /(1+e$^x$) = e$^x$-ln(e$^x$+1) + c
Work Step by Step
let ,
t = e$^x,
dt = e$^x dx ,
$\int$ t/(1+t) dt
$\int$ (t+1-1)/(1+t) dt
$\int$ (t+1)/(t+1) dt - $\int$ 1/(t+1)dt
$\int$ 1 dt - $\int$ 1/(1+t)
t- ln(t+1) + c
e$^x$- ln(e$^x$ + 1) + c
