Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 6 - Section 6.4 - Work - 6.4 Exercises - Page 459: 8

Answer

Work required to compress $10cm$ is equal to $3J$ Work required to compress to $25cm$ is equal to $6.75J$

Work Step by Step

We are given the natural length of $40cm$, force required ($60N$), and distance of compression ($10cm$), and are asked to find the work to compress both by $10cm$ and to compress to $25cm$. Before we can solve for any of these, we need to find the spring constant, for simplicity we convert centimeters into meters. $60=k*(0.1)$ $k=600$ Now that we know the spring constant, we can now solve the two questions To compress by $10cm$ $W=\int_{0}^{0.1}(600x)dx=3J$ To compress to $25cm$, we have to find the distance that it's compressed by $40-25=15$ The spring is being compressed by 15cm $W=\int_{0}^{0.15}(600x)dx=6.75J$
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