Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 6 - Section 6.1 - Areas Between Curves - 6.1 Exercises - Page 435: 49

Answer

$4232$ $cm^2$

Work Step by Step

Let $h(x)$ denote the height of the wing at $x$ $ cm$ from the left end. $A$ $\approx M_5=\frac{200-0}{5}[h(20)+h(60)+h(100)+h(140) +h(180)]$ $=40(20.3+29.0+27.3+20.5+8.7)$ $=40(105.8)$ $=4232$ $cm^2$
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