Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 6 - Section 6.1 - Areas Between Curves - 6.1 Exercises - Page 434: 25

Answer

$\frac{13}{5}$

Work Step by Step

$x^4=2-|x|$ $x=-1$, $x=1$ $\int_{-1}^1|x^4-2+|x||=$ $\int_{-1}^02+x-x^4dx+\int_0^12-x-x^4dx=\frac{13}{5}$
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