Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 5 - Section 5.5 - The Substitution Rule - 5.5 Exercises - Page 419: 66

Answer

$\int_{-\pi/3}^{\pi/3}x^4~sin~x~dx = 0$

Work Step by Step

The function $~~f(x) = sin~x~~$ is an odd function while $~~g(x) = x^4~~$ is an even function. Then $~~x^4~sin~x~~$ is an odd function. Therefore: $\int_{-\pi/3}^{\pi/3}x^4~sin~x~dx = 0$
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