Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 5 - Section 5.4 - Indefinite Integrals and the Net Change Theorem - 5.4 Exercises: 5

Answer

$$A=\frac{x^{2.3}}{2.3}+2x^{3.5}+C$$

Work Step by Step

$$A=\int(x^{1.3}+7x^{2.5})dx$$ $$A =\int{(x^{1.3})dx}+7\int(x^{2.5})dx$$ According to Table 1, we know that $\int(x^n)dx=\frac{x^{n+1}}{n+1}+C$ $(n\ne-1)$. Therefore, $$A=\frac{x^{2.3}}{2.3}+\frac{7x^{3.5}}{3.5}+C$$ $$A=\frac{x^{2.3}}{2.3}+2x^{3.5}+C$$
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