Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 5 - Section 5.2 - The Definite Integral - 5.2 Exercises: 17

Answer

$\int_{0}^{1} \frac{e^x}{1+x} dx$

Work Step by Step

We know the following $\int_{a}^{b} f(x)dx=\lim\limits_{n \to \infty}\sum\limits_{i=1}^{n} f(x_{i})\Delta x$ $\Delta x=\frac{a-b}{n}$ $x_{i}=a+i\Delta x$ In the problem we see that $f(x)=\frac{e^x}{1+x}$ and we are given the interval of [0,1] therefore the integral will be from 0 to 1. Therefore $\lim\limits_{n \to \infty}\sum\limits_{n=1}^{n} f(\frac{e^{x_i}}{1+x_i})\Delta x=\int_{0}^{1} \frac{e^x}{1+x} dx$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.