Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 4 - Section 4.9 - Antiderivatives - 4.9 Exercises - Page 357: 71

Answer

The cost of producing 100 items is $~~\$742.08$

Work Step by Step

$C'(x) = 1.92-0.002~x$ $C(x) = C_0+1.92~x-0.001~x^2$ It is given in the question that $C(1) = 562$ We can find $C_0$: $C(1) = C_0+1.92~(1)-0.001~(1)^2 = 562$ $C_0 = 562-1.92+0.001$ $C_0 = 560.08$ We can find $C(100)$, the cost of producing 100 items: $C(100) = 560.08+1.92~(100)-0.001~(100)^2$ $C(100) = 560.08+192-10$ $C(100) = 742.08$ The cost of producing 100 items is $~~\$742.08$
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