Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 4 - Section 4.7 - Optimization Problems - 4.7 Exercises: 3

Answer

10 and 10

Work Step by Step

The numbers are $x$ and $\frac{100}{x}$. We want to minimize $x+\frac{100}{x}$, which we will call $f(x)$. $f'(x)=1-\frac{100}{x^{2}}$, or $\frac{x^{2}-100}{x^{2}}$. Therefore there is a minimum value at $x=10$.
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