## Calculus: Early Transcendentals 8th Edition

$2.25$
$\lim\limits_{x \to 2} \frac{f(x)}{g(x)} = \lim\limits_{x \to 2} \frac{1.8(x-2)}{\frac{4}{5}(x-2)} = \frac{0}{0}$ L'Hospital: $\lim\limits_{x \to 2} \frac{1.8(1)}{\frac{4}{5}(1)} = 2.25$