Answer
$2.25$
Work Step by Step
$\lim\limits_{x \to 2} \frac{f(x)}{g(x)} = \lim\limits_{x \to 2} \frac{1.8(x-2)}{\frac{4}{5}(x-2)} = \frac{0}{0}$
L'Hospital:
$\lim\limits_{x \to 2} \frac{1.8(1)}{\frac{4}{5}(1)} = 2.25$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 4 - Section 4.4 - Indeterminate Forms and l''Hospital''s Rule - 4.4 Exercises - Page 311: 5
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