Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 4 - Section 4.4 - Indeterminate Forms and l''Hospital''s Rule - 4.4 Exercises: 5

Answer

$2.25$

Work Step by Step

$\lim\limits_{x \to 2} \frac{f(x)}{g(x)} = \lim\limits_{x \to 2} \frac{1.8(x-2)}{\frac{4}{5}(x-2)} = \frac{0}{0}$ L'Hospital: $\lim\limits_{x \to 2} \frac{1.8(1)}{\frac{4}{5}(1)} = 2.25$
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