Answer
$dV = 1.96 m^3$
Work Step by Step
$v = \frac{2}{3} \pi r^3$
$\frac{dv}{dr} = 2\pi r^2$
Solve for $dv$:
$dv = 2\pi r^2 dr$
$dv = 2\pi (25)^2 (0.0005)$
$dv = 1.96 m^3$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 3 - Section 3.10 - Linear Approximations and Differentials. - 3.9 Exercises - Page 257: 36
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