Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 3 - Review - Exercises: 45

Answer

$y'=3\tanh3x$

Work Step by Step

$y=\ln(\cosh3x)$ Start the differentiation process by using the chain rule: $y'=\dfrac{(\cosh3x)'}{\cosh3x}=...$ Apply the chain rule one more time to evaluate the derivative indicated in the numerator and simplify: $...=\dfrac{(3x)'\sinh3x}{\cosh3x}=\dfrac{3\sinh3x}{\cosh3x}=3\tanh3x$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.