Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 3 - Review - Exercises: 43

Answer

$y'=2x^{2}\cosh(x^{2})+\sinh(x^{2})$

Work Step by Step

$y=x\sinh(x^{2})$ Start the differentiation process by using the product rule: $y'=x[\sinh(x^{2})]'+(x)'\sinh(x^{2})=...$ Use the chain rule to evaluate the indicated derivatives: $...=x(x^{2})'\cosh(x^{2})+\sinh(x^{2})=...$ $...=(x)(2x)\cosh(x^{2})+\sinh(x^{2})=...$ $...=2x^{2}\cosh(x^{2})+\sinh(x^{2})$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.