## Calculus: Early Transcendentals 8th Edition

$y'=(\pi\ln10)(\sec^{2}\pi\theta)(10^{\tan\pi\theta})$
$y=10^{\tan\pi\theta}$ Start the differentiation process by using the chain rule: $y'=(10^{\tan\pi\theta})(\ln10)(\tan\pi\theta)'=...$ Use the chain rule again to evaluate the derivative indicated and simplify: $...=(10^{\tan\pi\theta})(\ln10)(\sec^{2}\pi\theta)(\pi\theta)'=...$ $...=(\pi\ln10)(\sec^{2}\pi\theta)(10^{\tan\pi\theta})$