Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 3 - Review - Exercises - Page 267: 32

Answer

$-e^{x}\sin e^{x}-\sin xe^{\cos x}$

Work Step by Step

$\dfrac {d}{dx}\left( e^{\cos x}+\cos \left( e^{x}\right) \right) =e^{\cos x}\times\left( \dfrac {d}{dx}\cos x\right) -\sin e^{x}\times \dfrac {d}{dx}\left( e^{x}\right) =-e^{x}\sin e^{x}-\sin xe^{\cos x}$
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