Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 3 - Review - Exercises: 20

Answer

$e^{xsecx}secx\left( 1+x\tan x\right) $

Work Step by Step

$\dfrac {d}{dx}e^{xsecx}=e^{xsccx}\times \dfrac {d}{dx}\left( xsecx\right) =e^{xsecx}secx\left( 1+x\tan x\right) $
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