## Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning

# Chapter 3 - Review - Exercises: 14

#### Answer

$y'=tan(x)$

#### Work Step by Step

Start with the function: $y=ln(sec(x))$. Use chain rule to differentiate: $y'=\frac{1}{sec(x)}*\frac{d}{x}(sec(x))$. Differentiate $sec(x)$ and plug in: $y' = \frac{sex(x)tan(x)}{sec(x)}$. Simplify to arrive at the answer: $y'=tan(x)$.

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