Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 2 - Section 2.8 - The Derivative as a Function - 2.8 Exercises - Page 160: 2

Answer

See the image below.

Work Step by Step

(a) The tangent line at $0$ is somewhat vertical with a slope of about $6$. (b) At the point $x=1$, we have a horizontal tangent line, so the derivative is $0$. (c) For this point, we have to estimate the number. If we draw a tangent line at that point, its value will be about $-\frac{3}{2}$. (d) At the point $x=3$ the slope is about $-1.3$. (e) At the point $x=4$, the tangent line becomes even less steep, but at the same time it starts to approach $0$. The tangent line is about $-0.8$. (f) At the point $x=5$, the slope continues to approach $0$ and gets a value of about $-\frac{1}{3}$. (g) At the point $x=6$, we have a horizontal tangent line, so the derivative is $0$. (From this point onward, the tangent line becomes positive). (h) At the point $x=7$, the tangent line becomes positive and its value is about $0.2$ (Note that all of these numbers are estimated. Other answers are possible.)
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.