Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 2 - Section 2.7 - Derivatives and Rates of Change - 2.7 Exercises - Page 150: 46

Answer

The rate of change of the temperature after an hour is $-\frac{5}{6}^oF/min$, or the turkey loses $\frac{5}{6}^oF$ every minute after an hour.

Work Step by Step

We would call the function from the graph $T=f(t)$ To estimaate the slope of the tangent at $t=60$, we would - pick 2 close points from $t=60$, which are $t=30$ and $t=90$ and figure out the values of $f(30)$ and $f(90)$ - Find the value of $\frac{f(90)-f(30)}{90-30}$. The result is the estimated slope of the tangent. From the graph, we see that $f(30)=150$ and $f(90)=100$ Therefore, the slope of the tangent is $$m=\frac{f(90)-f(30)}{90-30}=\frac{100-150}{60}=-\frac{5}{6}$$ The unit here is $^oF/min$. In conclusion, the rate of change of the temperature after an hour is $-\frac{5}{6}^oF/min$, or the turkey loses $\frac{5}{6}^oF$ every minute after an hour.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.