## Calculus: Early Transcendentals 8th Edition

a) -4, $f(-4)$ is not defined. -2, the left and right hand limits are not equa,l so the limit does not exist. 2, the left and right hand limits are not equal, so the limit does not exist. 4, the left and right hand limits are not equal, so the limit does not exist. b) -4, neither -2, left 2, right 4, right
a) explanation as above b) Since $f$ is not defined at $x = -4$, $f$ is not continuous from any side at $x = 4$. $f(-2) = \lim\limits_{x \to -2^-}f(x)$, so $f$ is continuous from the left. $f(2) = \lim\limits_{x \to 2^+}f(x)$, so $f$ is continuous from the right. $f(4) = \lim\limits_{x \to 4^+}f(x)$, so $f$ is continuous from the right.