Answer
$\lim\limits_{x \to 0} x^3 = 0$
Work Step by Step
Let $\epsilon \gt 0$ be given.
Let $\delta = \sqrt[3]{e}$
If $\vert x-0 \vert \lt \delta$, then $\vert x^3 - 0\vert \lt \delta^3 = \epsilon$
Therefore, $\lim\limits_{x \to 0} x^3 = 0$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 2 - Section 2.4 - The Precise Definition of a Limit - 2.4 Exercises - Page 114: 26
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
