Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 2 - Section 2.4 - The Precise Definition of a Limit - 2.4 Exercises - Page 114: 25

Answer

$\lim\limits_{x \to 0} x^2 = 0$

Work Step by Step

Let $\epsilon \gt 0$ be given. Let $\delta = \epsilon$ If $\vert x-0 \vert \lt \delta$, then $\vert x^2 - 0\vert \lt \delta = \epsilon$ Therefore, $\lim\limits_{x \to 0} x^2 = 0$
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