#### Answer

$\lim\limits_{x \to 4}\dfrac{x^{2}+3x}{x^{2}-x-12}=\infty$

#### Work Step by Step

Apply direct substitution first:
$\lim\limits_{x \to 4}\dfrac{x^{2}+3x}{x^{2}-x-12}=\dfrac{4^{2}+3(4)}{4^{2}-4-12}=\dfrac{28}{0}=\infty$

Published by
Cengage Learning

ISBN 10:
1285741552

ISBN 13:
978-1-28574-155-0

$\lim\limits_{x \to 4}\dfrac{x^{2}+3x}{x^{2}-x-12}=\infty$

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