Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 2 - Section 2.2 - The Limit of a Function - 2.2 Exercises - Page 94: 43

Answer

$\lim\limits_{x \to 0}(ln~x^2-x^{-2}) = -\infty$

Work Step by Step

$\lim\limits_{x \to 0}(ln~x^2-x^{-2})$ When $x$ is close to 0, $x^2$ is a very small positive number. Then $ln~x^2$ approaches $-\infty$ The value of $x^{-2} = \frac{1}{x^2}$ approaches $\infty$ Then, the value of $(ln~x^2-x^{-2})$ approaches $-\infty$
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