Answer
$\lim\limits_{x \to 2\pi^-}x\csc x=-\infty$
Work Step by Step
$\lim\limits_{x \to 2\pi^-}x\csc x=\lim\limits_{x \to 2\pi^-}\frac{x}{\sin x}=\frac{\lim\limits_{x \to 2\pi^-} x}{\lim\limits_{x \to 2\pi^-}\sin x}=\frac{2\pi^-}{0^-}=-\infty$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 2 - Section 2.2 - The Limit of a Function - 2.2 Exercises - Page 94: 39
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