Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 2 - Section 2.2 - The Limit of a Function - 2.2 Exercises: 35

Answer

$\lim\limits_{x \to 3+}\ln(x^2-9)=-\infty$

Work Step by Step

$\lim\limits_{x \to 3+}\ln(x^2-9)=\ln(9^+-9)=\ln0^+=-\infty$
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