Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 16 - Section 16.2 - Line Integrals - 16.2 Exercise - Page 1085: 29

Answer

$\frac{11}{8}-\frac{1}{e}$

Work Step by Step

We know that: $F(x,y)=(e^{x-1},x.y)$ $r(t)=(t^2,t^3); 0
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