Answer
$f_z(e,1,0)=1$.
Work Step by Step
$f(x,y,z)=x^{yz}$
$f_z=yx^{yz}\ln {(x)}\Rightarrow f_z(e,1,0)=(1)(e)^{(1)(0)}\ln {((e))}=1$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 14 - Section 14.3 - Partial Derivatives - 14.3 Exercise - Page 925: 44
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