Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 14 - Section 14.3 - Partial Derivatives - 14.3 Exercise - Page 924: 34

Answer

$w_x=y\sec^2{(x+2z)}$, $w_y=\tan{(x+2z)}$, $w_z=2y\sec^2{(x+2z)}$.

Work Step by Step

$w=y\tan{(x+2z)}$ In order to find $w_x$ we treat $y$ and $z$ as constants and differentiate with respect to $x$. $w_x=y\sec^2{(x+2z)}$ Analogously $w_y=\tan{(x+2z)}$ $w_z=2y\sec^2{(x+2z)}$
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