Answer
$f(x,y,z)$ is continuous for values $y \geq x^2$ and $z \gt 0$
Work Step by Step
We are given that $f(x,y,z)=\sqrt {y-x^2} \ln z$
The function $f(x,y,z)=\sqrt {y-x^2} \ln z$ includes a squared root, which is defined for positive values, and $\ln$, which is also defined for positive values.
Thus,
$y \geq x^2 $
and $z \gt 0$
Hence, $f(x,y,z)$ is continuous for values $y \geq x^2$ and $z \gt 0$
