Chapter 14 - Section 14.2 - Limits and Continuity - 14.2 Exercise - Page 911: 35

{$(x,y,z) | x^2+y^2+z^2\leq 1$}

We are given that $f(x,y,z)=arcsin(x^2+y^2+z^2)$ The function $f(x,y,z)=arcsin(x^2+y^2+z^2)$ represents a trigonometric function and $\sin x$ lies between -1 and +1. Thus, $ -1 \leq x^2+y^2+z^2\leq 1$ This means that $x^2+y^2+z^2\leq 1$ Hence, {$(x,y,z) | x^2+y^2+z^2\leq 1$}