Answer
The limit approaches $-\frac{2}{3}$
Work Step by Step
No issues arise if we evaluate the function at the given point, so the limit approaches $\frac{(2)^2(-1) + 2(-1)^2}{2^2 - (-1)^2} = -\frac{2}{3}$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 14 - Section 14.2 - Limits and Continuity - 14.2 Exercise - Page 910: 6
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