Calculus: Early Transcendentals 8th Edition

$\sqrt 3$
Given: $\lim\limits_{(x,y,z) ) \to (\pi,0,\frac{1}{3})} e^{y^{2}}tanxz$ Substitute $x=\pi,y=0,z=\frac{1}{3}$ $=\lim\limits_{(x,y,z) ) \to (\pi,0,\frac{1}{3})} e^{0^{2}}tan\frac{\pi}{3}$ $=1\times \sqrt 3$ $=\sqrt 3$ Hence, $\lim\limits_{(x,y,z) ) \to (\pi,0,\frac{1}{3})} e^{y^{2}}tanxz=\sqrt 3$