Answer
The formula for a sphere is:
$(x−h)^2+(y−k)^2+(z−l)^2=r^2$
h,k and l are the points given and r can be substituted for 5.
Plugging in these values we get:
$(x-3)^2+(y+6)^2+(z−4)^2=5^2$
$(x-3)^2+(y+6)^2+(z−4)^2=25$
Work Step by Step
The formula for a sphere is:
$(x−h)^2+(y−k)^2+(z−l)^2=r^2$
h,k and l are the points given and r can be substituted for 5.
Plugging in these values we get:
$(x-3)^2+(y+6)^2+(z−4)^2=5^2$
$(x-3)^2+(y+6)^2+(z−4)^2=25$
