Answer
Nearest to yz-plane: $C$
Lies in xz-plane: $A$
Work Step by Step
Nearest to yz-plane:
The point closest to the yz-plane will have the smallest |x|-value.
In this case, $C$'s |x|-value, $|2|$, is smaller than $A: |-4|$ and $B: |3|$.
Lies in the xz-plane:
A point that lies in the xz-plane will have a y-value of zero.
Point A is the only point that matches this criteria at $A(-4,0,1)$
