Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 11 - Section 11.3 - The Integral Test and Estimates of Sums - 11.3 Exercises - Page 726: 30

Answer

Convergent for $p\gt 1$.

Work Step by Step

$\int_{3}^{\infty}\frac{1}{xlnx[ln(lnx)]^{p}}dx=\int_{ln(ln3)}^{\infty}\frac{1}{u^{p}}du=\int_{ln(ln3)}^{\infty}u^{-p}du$ which is convergent for $p\gt 1$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.