Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 1 - Section 1.5 - Inverse Functions and Logarithms - 1.5 Exercises: 54

Answer

a) $x=e^e$ b) $x=\frac{\ln C}{a-b}$

Work Step by Step

a) $\ln (\ln x)=1$ $e^{\ln (\ln x)}=e^1$ $\ln x=e$ $x=e^e$ b) $e^{ax}=Ce^{bx}$ $\frac{e^{ax}}{e^{bx}}=C$ $e^{(a-b)x}=C$ $(a-b)x=\ln C$ $x=\frac{\ln C}{a-b}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.