Answer
a) $x=\pm\sqrt {e^3+1}$
b) $x=0, \ln2$
Work Step by Step
a) $\ln(x^2-1)=3$
$x^2-1=e^3$
$x^2=e^3+1$
$x=\pm\sqrt {e^3+1}$
b) $e^{2x}-3e^x+2=0$
$(e^x-1)(e^x-2)=0$
$e^x=1, x=0$ or $e^x=2, x=\ln2$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 1 - Section 1.5 - Inverse Functions and Logarithms - 1.5 Exercises - Page 67: 52
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