Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 1 - Section 1.5 - Inverse Functions and Logarithms - 1.5 Exercises: 52

Answer

a) $x=\pm\sqrt {e^3+1}$ b) $x=0, \ln2$

Work Step by Step

a) $\ln(x^2-1)=3$ $x^2-1=e^3$ $x^2=e^3+1$ $x=\pm\sqrt {e^3+1}$ b) $e^{2x}-3e^x+2=0$ $(e^x-1)(e^x-2)=0$ $e^x=1, x=0$ or $e^x=2, x=\ln2$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.