Answer
$\ln{\frac{bc^2}{d^3}}$
Work Step by Step
$\ln b+2\ln c-3\ln d=\ln b+\ln c^2-\ln d^3=\ln{\frac{bc^2}{d^3}}$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 1 - Section 1.5 - Inverse Functions and Logarithms - 1.5 Exercises - Page 67: 40
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