Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 1 - Section 1.4 - Exponential Functions - 1.4 Exercises - Page 54: 21

Answer

$f(x)=3\cdot2^x$

Work Step by Step

At $(1,6), 6=Cb^1=Cb$ $(i)$ At $(3,24), 24=Cb^3$ $(ii)$ $\frac{(ii)}{(i)}: b^2=4, b=\pm 2$ $\because$ The graph is monotically increasing, $b\gt 0,$ $\therefore b=2\rightarrow(i)$ $2C=6, C=3$ $\therefore f(x)=3\cdot2^x$
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