Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 1 - Section 1.4 - Exponential Functions - 1.4 Exercises: 1

Answer

$(a) 4$ $(b) x^{\frac{-4}{3}}$

Work Step by Step

$(a) \frac{4^{-3}}{2^{-8}}$ $=$ $\frac{2^{-6}}{2^{-8}}$ $=$ $2^{-6 + 8}$ $= 2^{2} = 4$ $(b) \frac{1}{\sqrt[3] {x^{4}}}$ = $x^{\frac{-4}{3}}$
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