Answer
$f^{-1}(x)=\frac{1-x}{2x-1}$
Work Step by Step
$f(x)=y=\frac{x+1}{2x+1}$
$2xy+y=x+1$
$x(2y-1)=1-y$
$f^{-1}(y)=\frac{1-y}{2y-1}$
$\therefore f^{-1}(x)=\frac{1-x}{2x-1}$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 1 - Review - Exercises - Page 70: 24
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