Answer
$f^{-1}(2)=1$
Work Step by Step
let $f^{-1}(2)=x, f(x)=2$
$2=2x+\ln x$
try $x=1$
RHS= $2\times1+\ln1=2+0=2$ =LHS
$\therefore f^{-1}(2)=1$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 1 - Review - Exercises - Page 70: 23
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