Answer
$f_n(x) = x^{2^{n+1}}$
Work Step by Step
We can evaluate the the first elements of the sequence:
$f_0(x) = x^2$
$f_1(x) = (x^2)^2 = x^4$
$f_2(x) = (x^4)^2 = x^8$
$f_3(x) = (x^8)^2 = x^{16}$
etc...
We can see that $f_n(x) = x^{2^{n+1}}$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 1 - Problems - Page 76: 19
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
