Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

APPENDIX E - Sigma Notation - E Exercises: 23

Answer

$3276$

Work Step by Step

We expand and simplify the sum: $\displaystyle \sum_{j=1}^{6}3^{j+1}$ $=3^{1+1}+3^{2+1}+3^{3+1}+3^{4+1}+3^{5+1}+3^{6+1}$ $=3^{2}+3^{3}+3^{4}+3^{5}+3^{6}+3^{7}$ $=9+27+81+243+729+2187$ $=3276$
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