Answer
$\displaystyle \sum_{i=0}^{5}2^{i}$
Work Step by Step
We contract the sum into sigma notation by noting that it follows the pattern of a sum of powers of 2 (e.g. $2^i$), starting with $1$ (e.g. $i=0$), and ending with $32$ (e.g. $i=5$).
$1+2+4+8+16+32=\displaystyle \sum_{i=0}^{5}2^{i}$
