Answer
$ sin(\pi-x)= sin x$
Work Step by Step
Need to prove $ sin({\pi}-x)=sinx$
$sin(A-B)=sinA cos B-cos A sin B$
Thus,
$ sin(\pi-x)=sin\pi cos x-cos \pi sin x$
$ sin(\pi-x)=0*cos x-(-1) sin x$
Hence, $ sin(\pi-x)= sin x$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
APPENDIX D - Trigonometry - D Exercises - Page A 32: 44
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