Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

APPENDIX D - Trigonometry - D Exercises - Page A 32: 34

Answer

$sin\theta=-\frac{3}{4}$ $cos\theta=\frac{\sqrt 7}{4}$ $tan\theta=-\frac{3}{ \sqrt 7}=-\frac{3\sqrt 7}{ 7}$ $sec \theta=\frac{4}{\sqrt 7}=\frac{4\sqrt 7}{ 7}$ $cot\theta=-\frac{\sqrt 7}{ 3}$

Work Step by Step

Since $csc\theta=-\frac{4}{3}$, we can label the hypotenuse side as having length 4 and the opposite side as having length 3. The Pythagorean Theorem gives adjacent side $=\sqrt {4^{2}-3^{2}}=\sqrt 7$ The other five trigonometric functions are given as follows: $sin\theta=-\frac{3}{4}$ $cos\theta=\frac{\sqrt 7}{4}$ $tan\theta=-\frac{3}{ \sqrt 7}=-\frac{3\sqrt 7}{ 7}$ $sec \theta=\frac{4}{\sqrt 7}=\frac{4\sqrt 7}{ 7}$ $cot\theta=-\frac{\sqrt 7}{ 3}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.